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Devin Bush Wins AFC Defensive Player of Week

Devin Bush Wins AFC Defensive Player of Week

Published 1 day, 9 hours ago
Description
Cleveland Browns linebacker Devin Bush secures AFC Defensive Player of the Week honors, following his impressive performance in the Week eighteen match against the Cincinnati Bengals. Bushs standout stats include fourteen tackles and a remarkable 97-yard interception return for a touchdown, which ties for the fourth-longest in Browns history. This is Bushs second weekly award, with his first win in Week six of 2019. He joins a list of Browns players honored this season, highlighting the teams strong defensive performance as the season concludes.

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